(2x+13)^(1/2)-5=x

Solution for (2x+13)^(1/2)-5=x equation:

(2x+13)^(1/2)-5=x

We move all terms to the left:

(2x+13)^(1/2)-5-(x)=0

We add all the numbers together, and all the variables

(2x+13)^(+1/2)-x-5=0

We add all the numbers together, and all the variables

-1x+(2x+13)^(+1/2)-5=0

We multiply all the terms by the denominator


-1x*2)+(2x+1+13)^(-5*2)=0

We add all the numbers together, and all the variables

-1x*2)+(2x+14)^(-10)=0

We add all the numbers together, and all the variables

-1x*2)+(2x=0

Wy multiply elements

-2x^2=0

a = -2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-2)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-4}=0$